Optimal. Leaf size=103 \[ 2 \cosh ^{-1}(a x)^3 \text{PolyLog}\left (2,-e^{2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x)^2 \text{PolyLog}\left (3,-e^{2 \cosh ^{-1}(a x)}\right )+3 \cosh ^{-1}(a x) \text{PolyLog}\left (4,-e^{2 \cosh ^{-1}(a x)}\right )-\frac{3}{2} \text{PolyLog}\left (5,-e^{2 \cosh ^{-1}(a x)}\right )-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (e^{2 \cosh ^{-1}(a x)}+1\right ) \]
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Rubi [A] time = 0.120114, antiderivative size = 103, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.7, Rules used = {5660, 3718, 2190, 2531, 6609, 2282, 6589} \[ 2 \cosh ^{-1}(a x)^3 \text{PolyLog}\left (2,-e^{2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x)^2 \text{PolyLog}\left (3,-e^{2 \cosh ^{-1}(a x)}\right )+3 \cosh ^{-1}(a x) \text{PolyLog}\left (4,-e^{2 \cosh ^{-1}(a x)}\right )-\frac{3}{2} \text{PolyLog}\left (5,-e^{2 \cosh ^{-1}(a x)}\right )-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (e^{2 \cosh ^{-1}(a x)}+1\right ) \]
Antiderivative was successfully verified.
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Rule 5660
Rule 3718
Rule 2190
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{\cosh ^{-1}(a x)^4}{x} \, dx &=\operatorname{Subst}\left (\int x^4 \tanh (x) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac{1}{5} \cosh ^{-1}(a x)^5+2 \operatorname{Subst}\left (\int \frac{e^{2 x} x^4}{1+e^{2 x}} \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )-4 \operatorname{Subst}\left (\int x^3 \log \left (1+e^{2 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+2 \cosh ^{-1}(a x)^3 \text{Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-6 \operatorname{Subst}\left (\int x^2 \text{Li}_2\left (-e^{2 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+2 \cosh ^{-1}(a x)^3 \text{Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x)^2 \text{Li}_3\left (-e^{2 \cosh ^{-1}(a x)}\right )+6 \operatorname{Subst}\left (\int x \text{Li}_3\left (-e^{2 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+2 \cosh ^{-1}(a x)^3 \text{Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x)^2 \text{Li}_3\left (-e^{2 \cosh ^{-1}(a x)}\right )+3 \cosh ^{-1}(a x) \text{Li}_4\left (-e^{2 \cosh ^{-1}(a x)}\right )-3 \operatorname{Subst}\left (\int \text{Li}_4\left (-e^{2 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+2 \cosh ^{-1}(a x)^3 \text{Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x)^2 \text{Li}_3\left (-e^{2 \cosh ^{-1}(a x)}\right )+3 \cosh ^{-1}(a x) \text{Li}_4\left (-e^{2 \cosh ^{-1}(a x)}\right )-\frac{3}{2} \operatorname{Subst}\left (\int \frac{\text{Li}_4(-x)}{x} \, dx,x,e^{2 \cosh ^{-1}(a x)}\right )\\ &=-\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+2 \cosh ^{-1}(a x)^3 \text{Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x)^2 \text{Li}_3\left (-e^{2 \cosh ^{-1}(a x)}\right )+3 \cosh ^{-1}(a x) \text{Li}_4\left (-e^{2 \cosh ^{-1}(a x)}\right )-\frac{3}{2} \text{Li}_5\left (-e^{2 \cosh ^{-1}(a x)}\right )\\ \end{align*}
Mathematica [A] time = 0.0292115, size = 103, normalized size = 1. \[ -2 \cosh ^{-1}(a x)^3 \text{PolyLog}\left (2,-e^{-2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x)^2 \text{PolyLog}\left (3,-e^{-2 \cosh ^{-1}(a x)}\right )-3 \cosh ^{-1}(a x) \text{PolyLog}\left (4,-e^{-2 \cosh ^{-1}(a x)}\right )-\frac{3}{2} \text{PolyLog}\left (5,-e^{-2 \cosh ^{-1}(a x)}\right )+\frac{1}{5} \cosh ^{-1}(a x)^5+\cosh ^{-1}(a x)^4 \log \left (e^{-2 \cosh ^{-1}(a x)}+1\right ) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.037, size = 165, normalized size = 1.6 \begin{align*} -{\frac{ \left ({\rm arccosh} \left (ax\right ) \right ) ^{5}}{5}}+ \left ({\rm arccosh} \left (ax\right ) \right ) ^{4}\ln \left ( 1+ \left ( ax+\sqrt{ax-1}\sqrt{ax+1} \right ) ^{2} \right ) +2\, \left ({\rm arccosh} \left (ax\right ) \right ) ^{3}{\it polylog} \left ( 2,- \left ( ax+\sqrt{ax-1}\sqrt{ax+1} \right ) ^{2} \right ) -3\, \left ({\rm arccosh} \left (ax\right ) \right ) ^{2}{\it polylog} \left ( 3,- \left ( ax+\sqrt{ax-1}\sqrt{ax+1} \right ) ^{2} \right ) +3\,{\rm arccosh} \left (ax\right ){\it polylog} \left ( 4,- \left ( ax+\sqrt{ax-1}\sqrt{ax+1} \right ) ^{2} \right ) -{\frac{3}{2}{\it polylog} \left ( 5,- \left ( ax+\sqrt{ax-1}\sqrt{ax+1} \right ) ^{2} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arcosh}\left (a x\right )^{4}}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{arcosh}\left (a x\right )^{4}}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{acosh}^{4}{\left (a x \right )}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arcosh}\left (a x\right )^{4}}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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